g^2+11g=468

Solution for g^2+11g=468 equation:

g^2+11g=468

We move all terms to the left:

g^2+11g-(468)=0

a = 1; b = 11; c = -468;
Δ = b2-4ac
Δ = 112-4·1·(-468)
Δ = 1993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1993}}{2*1}=\frac{-11-\sqrt{1993}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1993}}{2*1}=\frac{-11+\sqrt{1993}}{2}
$